Heron's Formula : In some cases, length of each side of the triangle are given but height of the triangle is neither given nor we are able to find in any way, then to find the area of such type of triangle, we use Heron's formula which is given below.
Area of triangle = , where a,b,c are length of the sides of a triangle and s is the semi-perimeter of the triangle i.e.
Example: Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. Solution : We divide the quadrilateral ABCD in two triangle ABC and ACD For ABC, a = 3, b = 4, c = 5 and Area (ABC) = = = 6 Similarly, for ACD, a = 5 cm, b = 5 cm, c = 4 cm and s = Area ( ACD ) = = = = Area of quadrilateral ABCD = Area of triangle ABC+ Area of triangle ACD = + |
If every side of a triangle is doubled then increase in area of triangle is : | |||
Right Option : C | |||
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The sides of a triangle are 50 cm 78 cm and 112 cm The smallest altitude is | |||
Right Option : B | |||
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Two adjacent sides of a parallelogram are 74 cm and 40 cm , if one of its diagonal is 102 cm , then find the area of the parallelogram. | |||
Right Option : C | |||
View Explanation |
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